For the roots of a quadratic Ax^2 + Bx + C = 0 to be rational, the discriminant D = B^2 - 4AC must be a perfect square. Here, D = (a - 3)^2 - 4(a + 2)(-(2a - 1)) = (a - 3)^2 + 4(a + 2)(2a - 1) = a^2 - 6a + 9 + 4(2a^2 + 3a - 2) = 9a^2 + 6a + 1 = (3a + 1)^2. Since the discriminant is a perfect square for any rational a, the roots are rational.