Multiple choice

A card is drawn from an ordinary pack of $52$ playing cards and a gambler bets it as a spade or an ace. The probability that he wins the bet is?

  1. $\dfrac{2}{13}$
  2. $\dfrac{3}{13}$
  3. $\dfrac{4}{13}$
  4. $\dfrac{1}{13}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total cards = 52. Spades = 13. Aces = 4. Ace of spades is counted in both, so total favorable outcomes = 13 + 4 - 1 = 16. Probability = 16/52 = 4/13.

AI explanation

The gambler wins if the card is any of the 13 spades or one of the three remaining aces, totaling 16 favorable outcomes. The probability of an event is the number of favorable outcomes divided by the total number of outcomes. Therefore, the probability is 16/52, which simplifies to 4/13.

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