Multiple choice technology programming languages

  1. public class Question { public static void main(String args[]) { int i=10; System.out.println("i="+++i); }

  1. i=0

  2. i=11

  3. invalid argument to operation

  4. none

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The expression +++i is syntactically invalid in Java. The ++ increment operator requires a variable operand immediately after it, but here it's followed by +, causing a compilation error.

AI explanation

To answer this question, let's analyze the given code:

public class Question {
  public static void main(String args[]) {
    int i=10;
    System.out.println("i="+++i);
  }
}

In this code, the expression "i="+++i is being printed using the System.out.println() method. Let's break down this expression:

  1. The +++i is a post-increment operator applied to the variable i. It increments the value of i by 1 and returns the original value of i.
  2. The "i=" is a string literal that is concatenated with the result of the post-increment operation.

So, the expression "i="+++i is equivalent to "i=" + (++i).

However, the code provided uses +++i instead of ++i. This is not valid syntax in Java. The ++ operator should be used either before or after the variable, not both. Therefore, the code will result in a compilation error, indicating an invalid argument to the operation.

Therefore, the correct answer is C) invalid argument to operation.