Multiple choice

Two chords AB and CD of a circle interest each other at P outside the circle. If $AB = 6 cm, BP=4cm$ and $PD=5cm$ then CD is

  1. $13$ cm
  2. $3$ cm
  3. $8 $cm
  4. $10$ cm
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For chords intersecting outside at P, the property is PA * PB = PC * PD. Given AB=6 and BP=4, then PA = AB + BP = 10. So, 10 * 4 = PC * 5, which gives PC = 8. Since CD = PC - PD, CD = 8 - 5 = 3 cm.

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