The chord through (2,1) to the circle $x^2-2x + y^2 - 2y + 1 = 0$ are bisected at the point $\displaystyle \left ( \alpha, \frac{1}{2} \right ),$ then the value of $\alpha$ is
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The chord through (2,1) to the circle $x^2-2x + y^2 - 2y + 1 = 0$ are bisected at the point $\displaystyle \left ( \alpha, \frac{1}{2} \right ),$ then the value of $\alpha$ is