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Multiple choice

If $\alpha and\beta$ are roots of the equation ${ x }^{ 2 }+px+\dfrac { 3p }{ 4 } =0,such$That $\left| \alpha -\beta \right| =\sqrt { 10 } $, then $p$ belongs to the se :

  1. $\left\{ 2,-5 \right\}$
  2. $\left\{ -3,2 \right\}$
  3. $\left\{- 2,5 \right\}$
  4. $\left\{ 3,-5 \right\}$
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