Three unbiased coins are tossed, what is probability of getting exactly two heads ?
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Three unbiased coins are tossed, what is probability of getting exactly two heads ?
Total outcomes for 3 coins = 2^3 = 8. Outcomes with exactly two heads: HHT, HTH, THH (3 outcomes). Probability = 3/8.
When three unbiased coins are tossed, the total number of possible outcomes in the sample space is 2 multiplied by itself 3 times, which equals 8. The favorable outcomes for getting exactly two heads are HHT, HTH and THH, totaling 3 possible combinations. Using the classical probability formula, the required probability is the number of favorable outcomes divided by the total outcomes, yielding 3 divided by 8. Therefore, the result is 3/8.