Multiple choice

Two die are thrown. Find the probability of the event that the product of numbers on their upper faces is $12$:

  1. $\displaystyle \frac{1}{12}$
  2. $\displaystyle \frac{1}{10}$
  3. $\displaystyle \frac{1}{9}$
  4. $\displaystyle \frac{1}{6}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total outcomes = 36. Favorable outcomes (product 12): (2,6), (6,2), (3,4), (4,3). Total = 4. Probability = 4/36 = 1/9.

AI explanation

When two dice are thrown, the total number of possible outcomes in the sample space is 36. To find the outcomes where the product of the numbers is 12, we identify the pairs (2,6), (6,2), (3,4) and (4,3). Thus, there are exactly 4 favorable outcomes. The required probability is 4 divided by 36, which simplifies to 1/9, resulting in 1/9.

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