Multiple choice

Two die are thrown find the probability of getting the sum of the numbers on their upper faces to be at most $3$.

  1. $\displaystyle \frac{1}{4}$
  2. $\displaystyle \frac{1}{6}$
  3. $\displaystyle \frac{1}{12}$
  4. $\displaystyle \frac{1}{36}$
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C Correct answer
Explanation

With two dice, there are 36 equally likely outcomes. A sum of at most 3 occurs for (1,1), (1,2), and (2,1), giving probability 3/36 = 1/12.

AI explanation

The total number of outcomes when throwing two dice is 36. To get a sum of at most 3, the possible pairs are (1,1), (1,2), and (2,1), meaning there are 3 favorable outcomes. Applying the classical probability formula, the probability is 3 divided by 36, which simplifies to 1/12.

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