A question paper has two parts P and Q, each containing 10 questions. If a student needs to choose 8 from part P and 4 from part Q, in how many ways can he do that ?

Choosing 8 questions from part P and 4 from part Q requires computing the combinations for each part independently and then multiplying them together. The number of ways to choose 8 from 10 is 10 C 8, and the number of ways to choose 4 from 10 is 10 C 4. We calculate 10 C 8 equals 45 and 10 C 4 equals 210, so multiplying them gives 45 times 210, which is 9450. The result is 9450.

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