Multiple choice

In a triangle ABC, $I$ be the incentre and $I_1, I_2$ and $I_3$ be the excetres. If 5 and 2 be the radius of circum circle and incircle respectively. Then $II_1.II_2.II_3=$

  1. 900

  2. 600

  3. 400

  4. 800
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The product of the distances from the incenter to the excenters is given by the formula II_1 * II_2 * II_3 = 16 * R^2 * r, where R is the circumradius and r is the inradius. Substituting the given values R = 5 and r = 2 into this formula, we get 16 * 5^2 * 2 = 800.

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