Find k for which the quadratic equations $4x^{2}+3kx+1=0$ has equal root.
Reveal answer
Fill a bubble to check yourself
Find k for which the quadratic equations $4x^{2}+3kx+1=0$ has equal root.
For equal roots, the discriminant D = b^2 - 4ac = 0. (3k)^2 - 4(4)(1) = 0. 9k^2 = 16. k^2 = 16/9. k = +/- 4/3.
For a quadratic equation to have equal roots, its discriminant must equal zero, so using the formula b squared minus 4ac equals 0. Substituting the coefficients gives (3k) squared minus 4(4)(1) equals 0, which simplifies to 9k squared minus 16 equals 0. Solving for k yields k squared equals 16 over 9, so k equals plus or minus 4 over 3.