Multiple choice

A supplies $20$ men who work for $8$ hrs. a day working for $6$ days. $B$ supplies $15$ men working at $9$ hrs. a day for $7$ days and $C$ supplies $10$ men working $6$ hrs. a day for $8$ days to do a certain job. If Rs. $636$ is paid for all labour, what is $C's$ share?

  1. $130$
  2. $125$
  3. $128$
  4. $135$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Calculate man-hours: A = 20*8*6 = 960. B = 15*9*7 = 945. C = 10*6*8 = 480. Total = 960 + 945 + 480 = 2385. C's share = (480 / 2385) * 636 = 128.

AI explanation

Using the man-hours method, the ratio of work done by A, B, and C is calculated by multiplying the number of men by the daily hours and the number of days. The ratios of man-hours are 960 for A, 945 for B, and 480 for C, which simplifies by dividing by 15 to a ratio of 64 to 63 to 32. Since the total ratio parts equal 159 and C represents 32 of those parts, C's share is found by multiplying 636 by 32 and dividing by 159, which results in Rs. 128.

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