A die is thrown twice. The probability of the sum being odd, is
- $\displaystyle\frac{1}{2}$
- $\displaystyle\frac{1}{3}$
- $\displaystyle\frac{1}{4}$
- $\displaystyle\frac{1}{6}$
Reveal answer
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A
Correct answer
Explanation
When throwing two dice, there are 36 total outcomes. The sum is odd if one die is even and the other is odd, or vice versa, which occurs in 18 cases. Thus, the probability is 18/36 = 1/2.
AI explanation
When a die is thrown twice, the total number of outcomes is 6 * 6 = 36. The sum of the two numbers is odd only when one number is even and the other is odd. There are 3 even and 3 odd numbers on a die, so there are 3 * 3 = 9 combinations for an even first and odd second, and 3 * 3 = 9 combinations for an odd first and even second. The total favorable outcomes are 9 + 9 = 18, making the probability 18/36 = 1/2.