Multiple choice

For the equation $3{x^2} + px + 3 + 0$ if one root is square of the other root, then $p=$

  1. $\displaystyle{1 \over 3}$
  2. $1$
  3. $-6$
  4. $3$
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C Correct answer
AI explanation

The equation provided is missing an equals sign and is interpreted as 3x^2 + px + 3 = 0. Let the roots be r and r^2, making their sum r + r^2 = -p/3 and their product r^3 = 3/3 = 1. Solving r^3 = 1 for real r gives r = 1. Substituting r = 1 into the sum equation gives 1 + 1 = -p/3, which results in p = -6.

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