The ${ 10 }^{ th }$ term of the series $1+5+13+29+...$ is

The differences between consecutive terms are 4, 8, and 16, forming a geometric progression with a ratio of 2. The general term of the series can be modeled as a_n = 1 + 4(2^n - 1), which simplifies to 2^(n + 1) - 3. For the 10th term, substituting n = 10 gives 2^11 - 3, resulting in 2048 - 3, which equals 2045.

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