Multiple choice

A man reduces his speed to two third to walk a distance and consequently becomes late by 1 hour With his usual speed he covers the same distance in

  1. $\displaystyle \frac{1}{4}$ hour
  2. $\displaystyle \frac{1}{2}$ hour

  3. 2 hours
  4. $\displaystyle 1\frac{1}{2}$ hours
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let usual speed be v and distance be d. Usual time t = d/v. New speed = (2/3)v. New time = d / ((2/3)v) = (3/2)t. We are given (3/2)t - t = 1 hour, so (1/2)t = 1, t = 2 hours.

AI explanation

Using the constant distance formula, the usual time is the product of the new time and the changed speed fraction. The new speed is two-thirds of the usual speed, meaning the new time is three-halves of the usual time, which makes the man 1 hour late. Therefore, half of the usual time equals 1 hour, making the usual time 2 hours.

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