Find the nth term and 9th term of the sequence 3, 7, 11, 15.........
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Find the nth term and 9th term of the sequence 3, 7, 11, 15.........
Sequence is 3, 7, 11, 15... This is an AP with a=3, d=4. nth term = a + (n-1)d = 3 + (n-1)4 = 4n - 1. 9th term = 4(9) - 1 = 35.
The sequence is an arithmetic progression with the first term a = 3 and the common difference d = 4. Using the formula for the nth term, Tn = a + (n - 1)d, we get Tn = 3 + (n - 1)4, which simplifies to 4n - 1. For the 9th term, we substitute n = 9 into the formula to get T9 = 4(9) - 1 = 35.