Multiple choice

A box contains 4 Green, 5 Blue and 3 Red balls. A ball is drawn at random. Find the probability that the selected ball is (i) Red in colour (ii) not Green in colour.

  1. (i)$\dfrac{1}{4}$    (ii) $\dfrac{2}{3}$ 
  2. (i)$\dfrac{4}{1}$    (ii) $\dfrac{2}{11}$ 
  3. (i)$\dfrac{5}{6}$    (ii) $\dfrac{5}{6}$ 
  4. (i)$\dfrac{13}{6}$    (ii) $\dfrac{2}{9}$ 
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A Correct answer
Explanation

Total balls = 4+5+3 = 12. (i) Probability of Red = 3/12 = 1/4. (ii) Probability of not Green = 1 - P(Green) = 1 - 4/12 = 1 - 1/3 = 2/3.

AI explanation

The total number of balls is 4 plus 5 plus 3, which equals 12. The probability of drawing a red ball is 3 divided by 12, or 1/4, and the probability of not drawing a green ball is (5 + 3) divided by 12, which is 8/12 or 2/3.

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