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Multiple choice

Find $m$, so that roots of the equation $(4 + m ) x^2 + (m + 1) x + 1 = 0$ may be equal.

  1. $5,-3$
  2. $5,3$
  3. $4,2$
  4. $1,-5$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

For equal roots, the discriminant D = b^2 - 4ac = 0. (m+1)^2 - 4(4+m)(1) = 0. m^2 + 2m + 1 - 16 - 4m = 0. m^2 - 2m - 15 = 0. (m-5)(m+3) = 0. So m = 5 or m = -3.

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