Multiple choice

A dice is thrown once. Find the probability of the event $E$ such that o utcome is more than 3.

  1. $\displaystyle \frac { 1 }{ 3 } $
  2. $\displaystyle \frac { 1 }{ 4 } $
  3. $\displaystyle \frac { 1 }{ 6 } $
  4. $\displaystyle \frac { 1 }{ 2 } $
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D Correct answer
Explanation

A standard die has six equally likely outcomes. Outcomes greater than 3 are 4, 5, and 6, so the probability is 3/6 = 1/2.

AI explanation

Using the classical definition of probability, the total number of possible outcomes when a die is thrown is 6. The favorable outcomes for getting a number more than 3 are 4, 5, and 6, giving 3 favorable outcomes. The required probability is 3 divided by 6, which equals 1/2.

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