If $b^2-4ac\geq 0$, then the root of quadratic equation $ax^2+bx+c=0$ is
- $\frac {b}{2a}\pm \frac {\sqrt {b^2-4a}}{2a}$
- $-\frac {b}{2a}\pm \frac {\sqrt {b^2+4ac}}{2a}$
- $\frac {b}{2a}\pm \frac {\sqrt {b^2+4ac}}{2a}$
- $-\frac {b}{2a}\pm \frac {\sqrt {b^2-4ac}}{2a}$
Reveal answer
Fill a bubble to check yourself
D
Correct answer
Explanation
The quadratic formula for ax^2 + bx + c = 0 is x = (-b +/- sqrt(b^2 - 4ac)) / 2a.
AI explanation
To find the roots of the general quadratic equation ax^2 + bx + c = 0, we use the quadratic formula. The formula states that the roots are given by x equals the opposite of b plus or minus the square root of the discriminant, all divided by 2a. The discriminant is defined as b^2 - 4ac. Therefore, the root of the quadratic equation is -b/2a plus or minus the square root of (b^2 - 4ac) divided by 2a, which matches the provided expression.