Multiple choice

Different words being formed by arranging the letters of the word "INTERMEDIATE". All the words obtained are written in the form of a dictionary, Number of permutations if the words start with E & ends with I

  1. $907200$
  2. $\displaystyle \frac{10!}{2!}$
  3. $3628800$

  4. None of these
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A Correct answer
Explanation

The word INTERMEDIATE has 12 letters: I(2), N(1), T(2), E(3), R(1), M(1), D(1), A(1). Fixing E at the start and I at the end leaves 10 letters to arrange: I(1), N(1), T(2), E(2), R(1), M(1), D(1), A(1). The number of permutations is 10! / (2! * 2!) = 3628800 / 4 = 907200.

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