Multiple choice

A bag A contains 4 green and 6 red balls. Another bag B contains 3 green and 4 red balls. If one ball is drawn from each bag, find the probability that both are green.

  1. 13/70

  2. 1/4

  3. 6/35

  4. 8/35

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Bag A: P(Green) = 4/10 = 2/5. Bag B: P(Green) = 3/7. Since events are independent, P(Both Green) = (2/5) * (3/7) = 6/35.

AI explanation

Bag A contains 4 green out of 10 total balls, giving a probability of 4/10 or 2/5 for drawing a green ball. Bag B contains 3 green out of 7 total balls, giving a probability of 3/7 for drawing a green ball. Using the multiplication rule for independent events, the probability that both balls drawn are green is (2/5) multiplied by (3/7), which equals 6/35.