If two dice are rolled find the probability that numbers coming up on both the dice will be multiples of $3$
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If two dice are rolled find the probability that numbers coming up on both the dice will be multiples of $3$
Multiples of 3 on a die are 3 and 6. For two dice, the favorable outcomes are (3,3), (3,6), (6,3), and (6,6), totaling 4 outcomes. The probability is 4/36, which simplifies to 1/9.
When two dice are rolled, the total number of outcomes in the sample space is 6 multiplied by 6, which equals 36. The multiples of 3 on a single die are 3 and 6, meaning there are 2 favorable numbers for each die. For both dice to show a multiple of 3, we multiply the individual probabilities: 2 divided by 6 multiplied by 2 divided by 6, yielding 4 divided by 36, which simplifies to 1 divided by 9.