If $10$ tractors can plough $\dfrac{1}{6}th$ of a field in $12$ days, how many days $20$ tractors will take to do the remaining work ?

Using the work equivalence formula where Tractors1 times Days1 divided by Work1 equals Tractors2 times Days2 divided by Work2, we set up the equation for the remaining 5/6 of the field. Substituting the values gives 10 tractors times 12 days divided by 1/6 equals 20 tractors times the unknown days divided by 5/6. Solving this yields 720 equals 24 times the unknown days, resulting in 30 days.

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