Two dice are thrown at a time, find the probability that the sum obtained is less than $6$.
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Two dice are thrown at a time, find the probability that the sum obtained is less than $6$.
Total outcomes = 36. Sum < 6: (1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1). Total = 10 outcomes. Probability = 10/36 = 5/18.
When two dice are thrown, the total number of possible outcomes is 36. The favorable outcomes for getting a sum less than 6 are the combinations that yield 2, 3, 4, or 5, which are (1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), and (4,1), totaling 10 combinations. Using the basic probability formula, the required probability is 10/36, which simplifies to 5/18.