Multiple choice

A box contains $5$ red balls, $4$ green balls and $7$ white balls. A ball is drawn at random from the box. Find the probability that the ball drawn is neither red nor white?

  1. $\dfrac{5}{6}$
  2. $\dfrac{1}{4}$
  3. $\dfrac{1}{3}$
  4. $\dfrac{2}{7}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total balls = 5+4+7 = 16. Neither red nor white means green. Number of green balls = 4. Probability = 4/16 = 1/4.

AI explanation

The total number of balls in the box is the sum of red, green, and white balls, which is 5 + 4 + 7 = 16. Since the ball drawn is neither red nor white, it must be green, and there are 4 green balls. Using the classical definition of probability, the likelihood is the number of favorable outcomes divided by the total outcomes, or 4/16. This simplifies to 1/4.

Keep practicing — related questions