Multiple choice

100 mL aqueous solution of glucose with osmotic pressure 1.2 atm at $25^oC$ is mixed with 300 mL aqueous solution of urea at 2.4 atm at $25^oC$. Calculate the osmotic pressure of mixture.

  1. 0.68 atm

  2. 1.68 atm

  3. 3.68 atm

  4. 2.10 atm
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D Correct answer
Explanation

Osmotic pressure is a colligative property. Pi_mix = (Pi1V1 + Pi2V2) / (V1 + V2) = (1.2 * 100 + 2.4 * 300) / 400 = (120 + 720) / 400 = 840 / 400 = 2.10 atm.

AI explanation

For a mixture of solutions, the final osmotic pressure is the mole-fraction-weighted average of the initial pressures, calculated as (100 multiplied by 1.2 plus 300 multiplied by 2.4) divided by 400. This evaluates to 840 divided by 400, resulting in an osmotic pressure of 2.10 atm.

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