The distance of the chord of length 16 cm from the center of the circle of diameter 20 cm is
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The distance of the chord of length 16 cm from the center of the circle of diameter 20 cm is
3 cm
4 cm
5 cm
6 cm
Radius = 10 cm. Chord length = 16 cm. A perpendicular from the center bisects the chord into two 8 cm segments. Using the Pythagorean theorem, distance^2 + 8^2 = 10^2. distance^2 = 100 - 64 = 36. distance = 6 cm.
The radius of the circle is half of the 20 cm diameter, which is 10 cm. The perpendicular from the center to the chord bisects the 16 cm chord, creating a right triangle with a leg of 8 cm and a hypotenuse of 10 cm. Using the Pythagorean theorem, the distance d is calculated as the square root of (10^2 - 8^2). Thus, the distance is the square root of 36, which is 6 cm.