Multiple choice

If $'b'$ men can do a piece of work in $'c'$ days, then the number of days taken by $'d'$ men to do $\displaystyle\frac{1}{m}$th of the same piece of work will be

  1. $\displaystyle\frac{bc}{d+m}$
  2. $\displaystyle\frac{bc}{dm}$
  3. $\displaystyle\frac{b+c}{d+m}$
  4. $\displaystyle\frac{b+c}{dm}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Work = b * c. New work = (b * c) / m. Number of days = (Work / Men) = (bc / m) / d = bc / (dm).

AI explanation

Using the proportionality rule that men and days are inversely proportional while work is directly proportional to days, the formula is (men1 * days1) / work1 = (men2 * days2) / work2. We have (b * c) / 1 = (d * days2) / (1 / m). Solving for days2 gives days2 = bc / (dm).