Eight tickets numbered 000, 010, 011, 011, 100, 101, 101 and 110 are placed in a bag. One ticket is drawn from the bag at random. Let A, B and C denote the following events: A-"the first digit is 0". B-"the second digit is 0" and C-"the third digit is 0". Then

To check for independence, the probability of the intersection of events must equal the product of their individual probabilities. The individual probabilities are P(A) = 3/8, P(B) = 2/8, and P(C) = 3/8. Checking the pairs, P(A and B) is 1/8 but P(A)P(B) is 3/32; P(B and C) is 1/8 but P(B)P(C) is 3/32; and P(A and C) is 1/8 but P(A)P(C) is 9/64. Since none of the intersections match the products of their individual probabilities, none of the events are independent.

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