Multiple choice

Two symmetrical dice are thrown. The probability that the product of the numbers on their upper most faces is $12$ is

  1. $\frac{1}{7}$
  2. $\frac{1}{8}$
  3. $\frac{1}{9}$
  4. $\frac{1}{6}$
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C Correct answer
Explanation

Two dice have 36 outcomes. Pairs with product 12 are (2,6), (6,2), (3,4), (4,3). There are 4 such pairs. Probability = 4/36 = 1/9.

AI explanation

The total number of outcomes when two symmetrical dice are thrown is 6 multiplied by 6, yielding 36. The product of the numbers on the uppermost faces is 12 for the outcomes (2, 6), (6, 2), (3, 4) and (4, 3). Thus, there are 4 favorable outcomes out of the 36 possible combinations. The required probability is 4 / 36, which simplifies to 1 / 9.

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