Multiple choice

The different words that can be using the letters of the word BHARAT so that these words will be contain B and H never together is

  1. 360

  2. 120

  3. 240

  4. 480
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total permutations of BHARAT (6 letters, A repeats twice) is 6! / 2! = 360. Permutations where B and H are together (treat BH as one unit) is 5! / 2! = 60. Since BH can be HB, multiply by 2 to get 120. Subtracting 120 from 360 gives 240.

AI explanation

The word BHARAT has 6 letters with A appearing twice, making the total arrangements 6 factorial divided by 2 factorial, which is 360. If B and H must be together, treat them as a single unit, creating 5 units to arrange, which results in 5 factorial divided by 2 factorial, or 60 arrangements. Since B and H can switch places within their unit, multiply by 2 to get 120 arrangements where they are together. The number of arrangements where they are never together is the total minus the together arrangements, so 360 minus 120 equals 240.

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