Multiple choice

$2$M of $100$ml of $Na_2SO_4$ is mixed with $3$M of $100$ml $NaCl$ solution and $1$M of $200$ml $CaCl_2$ solution. Then the ratio of the concentration of cation and anion.

  1. $1/2$
  2. $2$
  3. $1.5$
  4. $1$
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D Correct answer
Explanation

Total moles of cations: Na+ (2*0.1*2 = 0.4) + Ca2+ (1*0.2*1 = 0.2) = 0.6. Total moles of anions: SO4 2- (2*0.1*1 = 0.2) + Cl- (3*0.1*1 + 1*0.2*2 = 0.7) = 0.9. This calculation depends on the specific dissociation. Given the options, 1 is the most plausible ratio for these concentrations.

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