State True or False. The equation 2x$^{2}$ + 3x+1 = 0 has an irrational root
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State True or False. The equation 2x$^{2}$ + 3x+1 = 0 has an irrational root
True
False
The discriminant D = b^2 - 4ac = 3^2 - 4(2)(1) = 9 - 8 = 1. Since the discriminant is a perfect square, the roots are rational. Thus, the statement is false.
To find the roots of 2x^2 + 3x + 1 = 0, we can factor the quadratic into (2x + 1)(x + 1) = 0. Setting each factor to zero gives the solutions x = -1/2 and x = -1. Since both roots are rational numbers, the statement that the equation has an irrational root is false.