The roots of the following quadratic equations are r eal and distinct. $(x - 2a) (x - 2b) = 4ab$

Expanding the equation (x - 2a)(x - 2b) = 4ab gives x^2 - 2(a + b)x + 4ab = 4ab, which simplifies to x^2 - 2(a + b)x = 0. This factors to x(x - 2(a + b)) = 0, yielding two distinct real roots, 0 and 2(a + b). The statement is True.

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