Multiple choice

Solve the following quadratic equation by factorization, the roots are : (2x + 3)(3x - 7) = 0

  1. $-\dfrac{2}{3}, \, \dfrac{3}{7}$
  2. $-\dfrac{7}{2}, \, \dfrac{7}{3}$
  3. $-\dfrac{3}{2}, \, \dfrac{7}{3}$
  4. $-\dfrac{3}{7}, \, \dfrac{3}{5}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For (2x + 3)(3x - 7) = 0, set each factor to zero. 2x + 3 = 0 implies x = -3/2. 3x - 7 = 0 implies x = 7/3.

AI explanation

According to the zero product property, if (2x + 3)(3x - 7) = 0, then either 2x + 3 = 0 or 3x - 7 = 0. Solving the first equation for x gives 2x = -3 and x = -3/2. Solving the second equation gives 3x = 7 and x = 7/3. The roots are -3/2 and 7/3.

Keep practicing — related questions