Multiple choice

Three symmetrical dice are thrown. The probability that the same number will appear on each of them is:

  1. $\dfrac{1}{216}$
  2. $\dfrac{1}{36}$
  3. $\dfrac{35}{36}$
  4. $\dfrac{1}{35}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total outcomes = 6 * 6 * 6 = 216. Favorable outcomes (same number) = (1,1,1), (2,2,2), ..., (6,6,6) = 6. Probability = 6 / 216 = 1/36.

AI explanation

The total number of outcomes when three symmetrical dice are thrown is 6 times 6 times 6, which equals 216. The favorable outcomes are that all three dice show the same number, giving 6 possibilities: (1, 1, 1), (2, 2, 2), (3, 3, 3), (4, 4, 4), (5, 5, 5), and (6, 6, 6). The probability is 6 divided by 216, which simplifies to 1/36.

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