Multiple choice

A coin whose faces are mark 2, 3 is thrown 5 times. What is the probability of throwing a total of 127?

  1. $ \displaystyle \frac{11}{16} $
  2. $ \displaystyle \frac{1}{32} $
  3. $ \displaystyle \frac{5}{16} $

  4. 0
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D Correct answer
Explanation

The maximum possible sum with 5 throws of a coin marked 2 and 3 is 5 * 3 = 15. It is impossible to reach a sum of 127.

AI explanation

The coin is marked with 2 and 3, meaning the minimum possible total sum after 5 throws is 10, obtained by rolling a 2 on every throw. The maximum possible total sum after 5 throws is 15, obtained by rolling a 3 on every throw. Because 127 falls completely outside the range of possible sums, it is an impossible event. The probability of an impossible event is always 0.

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