The area of the circle whose centre is (1,2) and which passes through the point (4,6) is
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The area of the circle whose centre is (1,2) and which passes through the point (4,6) is
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The radius is the distance between (1,2) and (4,6): r = sqrt((4-1)^2 + (6-2)^2) = sqrt(3^2 + 4^2) = sqrt(9+16) = 5. Area = pi * r^2 = 25pi.
The radius of the circle is the distance between the center (1,2) and the point (4,6), calculated using the distance formula as the square root of ((4-1) squared + (6-2) squared). This gives the square root of (9 + 16), which is the square root of 25, so the radius is 5 units. The area of the circle is pi * r squared, giving pi * 5 squared = 25pi.