The diameter of a circle found by measurement $5.2$ cms with a maximum error $0.05$ cms. The maximum error in its area is?
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The diameter of a circle found by measurement $5.2$ cms with a maximum error $0.05$ cms. The maximum error in its area is?
Area A = pi * r^2 = pi * (d/2)^2 = (pi/4) * d^2. The error in area dA = (pi/4) * 2 * d * dd = (pi/2) * d * dd. Substituting d=5.2 and dd=0.05 gives (3.14159/2) * 5.2 * 0.05 = 0.408, which rounds to 0.41.
The area of a circle is pi multiplied by the radius squared, so the approximate error in the area can be found using differentials. Taking the derivative of the area gives 2 multiplied by pi and the radius, meaning the approximate error is 2 times pi times r times the error in the radius. The radius is 5.2 divided by 2, which is 2.6 centimeters, and the radius error is 0.05 divided by 2, which is 0.025 centimeters. Multiplying 2 by 3.14, 2.6 and 0.025 gives a maximum error in the area of approximately 0.4082, which rounds to 0.41 square centimeters.