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Multiple choice

On a normal standard die one of the $21$ dots from any one of the six faces is removed at random with each dot equally likely to be chosen. The die is then rolled. The probability that the top face has an odd number of dots is

  1. $\dfrac {5}{11}$
  2. $\dfrac {5}{12}$
  3. $\dfrac {11}{21}$
  4. $\dfrac {6}{11}$
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C Correct answer

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