Two persons P and Q are start at the same time from city A for city B 60 km away P travels R kmph slower than Q Q reaches city B and AT once Turms back meeting P 12 km from city b What is speed of P ?

When Q meets P, Q has traveled 60 km to the city plus 12 km back, which equals 72 km, while P has traveled 60 km minus 12 km, which equals 48 km. Because they started at the same time and traveled for the same amount of time until they met, the ratio of their speeds is 72 to 48, or 3 to 2. Let the speed of P be 2x and the speed of Q be 3x; since P is slower than Q by 4 kmph, 3x minus 2x equals 4, so x is 4. Therefore, the speed of P is 2x, which equals 8 kmph.

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