Multiple choice

Four dice are rolled. The number of ways in which atleast one die shows $3$, is

  1. $625$
  2. $671$
  3. $1296$
  4. $1256$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total outcomes for 4 dice = 6^4 = 1296. Outcomes with no 3s = 5^4 = 625. Outcomes with at least one 3 = 1296 - 625 = 671.

AI explanation

When rolling four dice, the total number of possible outcomes is 6^4, which equals 1296. To find the outcomes where at least one die shows 3, we use the complementary event principle by calculating the total outcomes minus the outcomes where no die shows 3. The number of ways no die shows 3 is 5^4, which equals 625. Therefore, the required number of ways is 1296 minus 625, which is 671.

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