When tossing a fair $6$-sided die, the probability of not getting $3$ would be
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When tossing a fair $6$-sided die, the probability of not getting $3$ would be
A fair 6-sided die has outcomes {1, 2, 3, 4, 5, 6}. The probability of getting a 3 is 1/6. The probability of not getting a 3 is 1 - 1/6 = 5/6.
By the complementary event probability rule, the probability of an event not occurring equals 1 minus the probability of the event occurring. The probability of getting a 3 on a 6-sided die is 1/6. Therefore, the probability of not getting a 3 is 1 - 1/6 = 5/6.