Multiple choice

If one roots of the quadratic equation is $ \displaystyle \sqrt{3+1} $ , the equation is

  1. $ \displaystyle x^{2}-2x-\sqrt{3}=0 $
  2. $ \displaystyle x^{2}-2\sqrt{3}x+2=0 $
  3. $ \displaystyle x^{2}-x-2=0 $
  4. $ \displaystyle x^{2}+2\sqrt{3}x+23=0 $
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The given root is sqrt(3 + 1) = 2. Among the options, x^2 - x - 2 factors as (x - 2)(x + 1), so it has 2 as a root.

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