Two symmetrical dice are thrown. The probability of getting a sum of $8$ points is
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Two symmetrical dice are thrown. The probability of getting a sum of $8$ points is
Total outcomes = 36. Sum of 8: (2,6), (3,5), (4,4), (5,3), (6,2). There are 5 such outcomes. Probability = 5/36.
The total number of possible outcomes when two symmetrical dice are thrown is 6 times 6, which equals 36. The favorable outcomes for getting a sum of 8 are (2, 6), (3, 5), (4, 4), (5, 3) and (6, 2), giving 5 favorable combinations. Using the classical definition of probability, the required probability is the number of favorable outcomes divided by the total outcomes, which is 5 divided by 36. The probability of getting a sum of 8 points is 5/36.