A coin is tossed $3$ times. The probability of obtaining two heads will be
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A coin is tossed $3$ times. The probability of obtaining two heads will be
Tossing a coin 3 times results in 2^3 = 8 outcomes. The outcomes with exactly two heads are (H,H,T), (H,T,H), (T,H,H). There are 3 such outcomes, so the probability is 3/8.
When a coin is tossed 3 times, the total number of possible outcomes is 2 cubed, which equals 8. The combinations with exactly two heads are HHT, HTH, and THH, yielding 3 favorable outcomes. By the basic probability formula, 3 divided by 8 gives the final result. The probability is 3/8.