Multiple choice

Two symmetrical dice are thrown at a time. The probability that they show different faces is

  1. $\dfrac{5}{6}$
  2. $\dfrac{1}{36}$
  3. $\dfrac{25}{36}$
  4. $\dfrac{1}{18}$
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A Correct answer
Explanation

Total outcomes for two dice are 36. The outcomes where faces are the same are (1,1), (2,2), (3,3), (4,4), (5,5), (6,6), which are 6 cases. The probability of same faces is 6/36 = 1/6. The probability of different faces is 1 - 1/6 = 5/6.

AI explanation

When two dice are thrown, the total number of possible outcomes is 36, and 6 of these outcomes have equal faces, which are (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), and (6, 6). The number of outcomes with different faces is 36 minus 6, which equals 30. By the basic probability formula, 30 divided by 36 simplifies to 5/6. The probability is 5/6.

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